Date: Fri, 30 Mar 2001 02:59:04 +0200
From: Erwin Harte
Subject: Re: [DGD]Adding character to string

On Fri, Mar 30, 2001 at 01:57:32AM +0200, Erwin Harte wrote:
> On Fri, Mar 30, 2001 at 01:30:43AM +0200, Frantisek Fuka wrote:
[...]
> 
> I'd do it this way:
> 
>     int    i, len;
>     string out;
> 
>     out = implode(explode("\n" + msg + "\n", "\n"), "\r\n");
>     for (i = 0, len = strlen(out); i < len; i++) {
>         out[i] &= 0x7f;
>     }

Silly me, there I went and ignored the charset_output(..) function
you're using.  Replace the 'out[i] &= 0x7f' with:

          if (out[i] & 0x80) {
              out[i] = charset_output(out[i] - 0x80);
          }

An alternative approach (which, I should say, was suggested by Dworkin
and not one I came up with) would be to use parse_string() with a
grammar like this:

    lo = /[\x00-\x7f]+/
    hi = /[\x00-\x7f]+/

    text = chunks chunk
    text = chunk

    chunk = lo
    chunk = hi ? convert_output

Where convert_output would be a function like this:

    string
    convert_output(mixed *tree)
    {
        int i, len;
        string str;

        str = tree[0];
        for (i = 0, len = strlen(str); i < len; i++) {
            str[i] = charset_output(str[i] - 0x80);
        }
        return ({ str });
    }

The two functions required for the text grammar-rules are left as an
exercise to the reader. ;-)

Erwin.
-- 
Erwin Harte      : `Don't mind Erwin, he gets crabby. :)'